c - Trying to randomly generate a string in order to get a conditional to execute -

seems strings in c weak point, need guys' again. should have included in first one, apologize that.

so have function got working correctly, fills string random chars set {r, e, s, e, t} , returns it:

char *inputstring() {     static char string[6];     const char *digits = "reset";     int i;      (i = 0; < 5; i++)      {         string[i] = digits[ rand() % 4 + 0 ];     }      return string; } 

so char @ string[5] '\0', correct? , string[1] through string[4] random combinations of other characters (r, e, s, e, t).

now, have function calls one. these purpose of trying printf statement execute:

other_fxn()  {   char *s;    while (1)    {      s = inputstring();     if (s[0] == 'r'&& s[1] == 'e' && s[2] == 's' && s[3] == 'e' && s[4] == 's'         && s[5] == '\0')      {       printf('worked!\n');       break;     }   } } 

main:

{    srand(time(null));    other_fxn(); } 

it compiles fine loop runs forever, if statement never executing. can me out why won't execute. once again.

  while (1)    {       s = inputstring();     if (s[0] == 'r'&& s[1] == 'e' && s[2] == 's' && s[3] == 'e' && s[4] == 't'         && s[5] == '\0')      {       printf('worked!\n');       break;     }    } 

first of all, in example looking word "reses". , don't change string inside loop. out of loop if random string reset after initial generation. don't know why need this, code above out of loop. maybe not soon, will.

also, one:

string[i] = digits[ rand() % 4 + 0 ]; 

why + 0? , why % 4, not % 5?

better go this:

char *inputstring() {     static char string[6];     const char *digits = "reset";     (int = 0; < 5; i++)      {         string[i] = digits[ rand() % 5];     }     return string; } 

and try using debugger, helps.