javascript - JQuery - Show/hide 2 divs with 1 button and change value of button -

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i've trying make when click button hide 1 div , show @ same time change value of button reflect different content of divs.

i've been able create 2 functions when put them seems break.

here's show/hide function

javascript :

function change() {      if (document.getelementbyid('tabs')) {         if (document.getelementbyid('tabs').style.display == 'none') {         document.getelementbyid('tabs').style.display = 'block';         document.getelementbyid('parklist').style.display = 'none';}         else {         document.getelementbyid('tabs').style.display = 'none';         document.getelementbyid('parklist').style.display = 'block';}        }      }

and here's value change function

javascript:

function change( el ) {   if ( el.value === "div1" )       el.value = "div2";   else       el.value = "div1";  }

and here's html both

html:

<div id="tabs">div 1</div> <div id="parklist">div 2</div>  <input type="submit" value="div1" onclick="return change(this);"/>

i'm bit of novice great.

you can try jquery toogle() function switch display property of matched element.

  • by default parklist div hidden.
  • add click listener on submit button.
  • toggle display property of both divs on click of submit button
  • set value of submit button visible div's content. 

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>    <div id="tabs">div 1</div>  <div id="parklist" style="display:none">div 2</div>    <input type="submit" value="div 1"/>    <script>        var submit = $('input[type="submit"]');    var tabs = $('#tabs');    var parklist = $('#parklist');        submit.click(function(e){       tabs.toggle();       parklist.toggle();             if(tabs.css('display') == 'none'){         submit.val(parklist.text());       }else{         submit.val(tabs.text());       }    });      </script>


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