python - create a dict with unique keys and various list values from a tuple -

i have list of tuples one:

[('id1', 'text1', 0, 'info1'),  ('id2', 'text2', 1, 'info2'),  ('id3', 'text3', 1, 'info3'),  ('id1', 'text4', 0, 'info4'),  ('id4', 'text5', 1, 'info5'),  ('id3', 'text6', 0, 'info6')] 

i want convert dict, keeping ids keys , other values lists of tuples, expanding ones aready exist:

{'id1': [('text1', 0, 'info1'),          ('text4', 0, 'info4')],  'id2': [('text2', 1, 'info2')],  'id3': [('text3', 1, 'info3'),          ('text6', 0, 'info6')],  'id4': [('text5', 1, 'info5')]} 

right use pretty simple code:

for x in list:   if x[0] not in list: list[x[0]] = [(x[1], x[2], x[3])]   else: list[x[0]].append((x[1], x[2], x[3])) 

i beleive there should more elegant way achieve same result, generators maybe. ideas?

a useful function appending lists inside dictionary these kind of problems dict.setdefault. can use retrieve existing list dictionary, or add empty 1 if missing, so:

data = [('id1', 'text1', 0, 'info1'),         ('id2', 'text2', 1, 'info2'),         ('id3', 'text3', 1, 'info3'),         ('id1', 'text4', 0, 'info4'),         ('id4', 'text5', 1, 'info5'),         ('id3', 'text6', 0, 'info6')]  x = {} tup in data:     x.setdefault(tup[0], []).append(tup[1:]) 

result:

{'id1': [('text1', 0, 'info1'), ('text4', 0, 'info4')],  'id2': [('text2', 1, 'info2')],  'id3': [('text3', 1, 'info3'), ('text6', 0, 'info6')],  'id4': [('text5', 1, 'info5')]} 

alternatively, use collections.defaultdict:

from collections import defaultdict x = defaultdict(list) tup in data:     x[tup[0]].append(tup[1:]) 

which has similar results.